Penentuan (analisis) NaCl di dalam larutan menggunakan alat Potensiometer

Alat yang digunakan
Potentiometer = 751 GPD Titrino / Titroprocessor
Electrode = 6.0430.100 Ag Titrode amalgamated; input 1

Pereaksi
c(AgNO3) = 0.1 mol/L; D0

Contoh
20 mL larutan contoh
5 mL c(HNO3) = 2 mol/L
30 mL air destilasi


Rangkuman
· Perhitungan

NaCl=EP1*C01*C02*C03/C00;2;%

NaCl = kandungan NaCl di dalam larutan in %
C00 = banyaknya contoh (10 g / 100 = 0.1 g)
C01 = Berat molekul dari NaCl (58.44 g/mol)
C02 = konsentrasi larutan titer (0.1 mol/L)
C03 = faktor konversi mL Þ L dan % (0.001*100 = 0.1)

. Jawaban

NaCl = 8.070 x 58.44 x 0.1 x 0.1 / 0.1 = 47.16 %

EP1 = 8.070 mL
C00 = 0.1 g

· Sample preparation:
Dissolve 10 g (1 cube) conc. broth in 800 mL boiling dist. water. Rinse
this solution in a 2000 mL measuring flask. Allow to cool down and fill
up to the mark. Filter with a folded filter. Take 20 mL aliquots.

Literature
· Metrohm Application Bulletin No. 130: Chloride titrations with
potentiometric end-point indication.